PHP结合HTML5使用FormData对象提交表单及上传图片

jopen 5年前

FormData 对象,可以把form中所有表单元素的name与value组成一个queryString,提交到后台。在使用Ajax提交时,使用FormData对象可以减少拼接queryString的工作量。

使用FormData对象

1.创建一个FormData空对象,然后使用append方法添加key/value

var formdata = new FormData();  formdata.append('name','fdipzone');  formdata.append('gender','male');

2.取得form对象,作为参数传入到FormData对象

<form name="form1" id="form1">  <input type="text" name="name" value="fdipzone">  <input type="text" name="gender" value="male">  </form>
var form = document.getElementById('form1');  var formdata = new FormData(form);

使用FormData提交表单及上传文件:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">  <html>   <head>    <meta http-equiv="content-type" content="text/html; charset=utf-8">    <title> FormData Demo </title>    <script src="//code.jquery.com/jquery-1.11.0.min.js"></script>      <script type="text/javascript">    <!--      function fsubmit(){          var data = new FormData($('#form1')[0]);          $.ajax({              url: 'server.php',              type: 'POST',              data: data,              dataType: 'JSON',              cache: false,              processData: false,              contentType: false          }).done(function(ret){              if(ret['isSuccess']){                  var result = '';                  result += 'name=' + ret['name'] + '<br>';                  result += 'gender=' + ret['gender'] + '<br>';                  result += '<img src="' + ret['photo']  + '" width="100">';                  $('#result').html(result);              }else{                  alert('提交失敗');              }          });          return false;      }    -->    </script>     </head>     <body>      <form name="form1" id="form1">          <p>name:<input type="text" name="name" ></p>          <p>gender:<input type="radio" name="gender" value="1">male <input type="radio" name="gender" value="2">female</p>          <p>photo:<input type="file" name="photo" id="photo"></p>          <p><input type="button" name="b1" value="submit" onclick="fsubmit()"></p>      </form>      <div id="result"></div>   </body>  </html>

server.php

<?php  $name = isset($_POST['name'])? $_POST['name'] : '';  $gender = isset($_POST['gender'])? $_POST['gender'] : '';    $filename = time().substr($_FILES['photo']['name'], strrpos($_FILES['photo']['name'],'.'));    $response = array();    if(move_uploaded_file($_FILES['photo']['tmp_name'], $filename)){      $response['isSuccess'] = true;      $response['name'] = $name;      $response['gender'] = $gender;      $response['photo'] = $filename;  }else{      $response['isSuccess'] = false;  }    echo json_encode($response);  ?>

PHP结合HTML5使用FormData对象提交表单及上传图片

 来源:傲雪星枫